Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:Flip-flops sample synchronous inputs (D, J/K, T with enables) around an active clock transition. Two key timing specs guarantee correct sampling: setup time and hold time. This item checks your understanding of how short hold time supports correct state capture.
Given Data / Assumptions:
Concept / Approach:If inputs meet setup and hold, the device samples reliably at the active edge and the output transitions to the state commanded by those inputs. Many modern flip-flops specify minimal or even zero hold time thanks to internal clocking schemes, which aligns with the statement’s “generally short enough.”
Step-by-Step Solution:
Ensure synchronous inputs are valid and stable for at least t_setup before the active edge.Maintain inputs stable for at least t_hold after the edge.Given small t_hold, the output resolves to the state defined immediately prior to the edge.Therefore, the statement is correct under standard timing practice.Verification / Alternative check:Consult device timing diagrams: the sampling instant is at the active edge, and output changes after t_co (clock-to-output delay) when setup/hold are met.
Why Other Options Are Wrong:
Incorrect: Conflicts with basic edge-triggered sampling behavior.True only for asynchronous inputs: Asynchronous inputs are not governed by setup/hold in the same way and can violate metastability rules.True only for negative-edge devices: Applies to either edge; polarity is irrelevant.Common Pitfalls:Ignoring hold time because it is “small”; changing inputs right at the edge; mixing asynchronous set/reset with synchronous data timing.
Final Answer:Correct
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