In algebraic identities, you are given that a^3 + b^3 = 28 and a + b = 4 for real numbers a and b. Using a standard identity for a^3 + b^3, find the exact value of ab.

Difficulty: Medium

Correct Answer: 3

Explanation:


Introduction / Context:
This question checks whether you can connect a sum of cubes with the sum of numbers using the identity for a^3 + b^3. It is a common simplification and identity-based technique in aptitude algebra.


Given Data / Assumptions:

  • a^3 + b^3 = 28
  • a + b = 4
  • a and b are real numbers


Concept / Approach:
Use the identity: a^3 + b^3 = (a + b)^3 - 3ab(a + b). Since a^3 + b^3 and (a + b) are given, this identity becomes a direct equation in ab.


Step-by-Step Solution:

Write the identity: a^3 + b^3 = (a + b)^3 - 3ab(a + b). Substitute a^3 + b^3 = 28 and a + b = 4. 28 = (4)^3 - 3ab*(4). Compute 4^3: 28 = 64 - 12ab. Rearrange: 12ab = 64 - 28 = 36. So ab = 36/12 = 3.


Verification / Alternative check:
If ab = 3 and a + b = 4, then a and b are roots of t^2 - 4t + 3 = 0, giving t = 1 and 3. Then a^3 + b^3 = 1^3 + 3^3 = 28, which matches perfectly.


Why Other Options Are Wrong:

2 or 1 come from using (a + b)^3 - 3ab incorrectly (missing the factor (a + b)). -3 is possible only if the cube-sum were larger than (a + b)^3, which it is not here. 8 is a random product guess that does not satisfy the identity.


Common Pitfalls:
Forgetting that the identity is (a + b)^3 - 3ab(a + b), not (a + b)^3 - 3ab. Also, many learners forget to multiply by (a + b) in the last term.


Final Answer:
ab = 3

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