Three people A, B, and C have these annual average income pairs: Average(A, B) = ₹80,000 Average(B, C) = ₹75,000 Average(C, A) = ₹78,000 Find the annual income of A (in ₹).

Difficulty: Medium

Correct Answer: ₹83,000

Explanation:


Introduction / Context:
This problem tests average-based equations. Pairwise averages can be converted into pairwise sums. Once you have the sums (A+B), (B+C), and (C+A), you can combine them to get A+B+C and then isolate A.


Given Data / Assumptions:

  • (A + B)/2 = 80,000
  • (B + C)/2 = 75,000
  • (C + A)/2 = 78,000
  • All incomes are annual and measured in ₹.


Concept / Approach:
Convert averages to sums: A + B = 2*80,000 B + C = 2*75,000 C + A = 2*78,000 Then add all three equations. The left side becomes 2(A + B + C). Solve for A by subtracting (B + C) from (A + B + C).


Step-by-Step Solution:

From (A + B)/2 = 80,000, get A + B = 160,000. From (B + C)/2 = 75,000, get B + C = 150,000. From (C + A)/2 = 78,000, get C + A = 156,000. Add: (A + B) + (B + C) + (C + A) = 160,000 + 150,000 + 156,000. Left side becomes 2(A + B + C). Right side = 466,000. So A + B + C = 466,000/2 = 233,000. Now A = (A + B + C) - (B + C) = 233,000 - 150,000 = 83,000.


Verification / Alternative check:
If A = 83,000 then A + B = 160,000 implies B = 77,000. Then B + C = 150,000 gives C = 73,000. Check C + A = 73,000 + 83,000 = 156,000 which matches the third equation.


Why Other Options Are Wrong:

₹81,000 or ₹82,000 happen if you divide 466,000 by 3 incorrectly (it must be divided by 2 first). ₹84,000 is an off-by-1,000 arithmetic slip. ₹80,000 confuses A's value with the average of A and B.


Common Pitfalls:
Forgetting that the average of two numbers is half their sum, or adding averages directly without converting to sums first.


Final Answer:
₹83,000

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