Fill operators to make a true statement — Replace the asterisks with the correct signs so that the equality holds. 9 * 3 * 3 * 3 * 6

Introduction / Context:
We must choose a sequence of four symbols that, when inserted between the five numbers (9, 3, 3, 3, 6), yields a true equation under standard arithmetic precedence. These puzzles test careful operator placement and precedence awareness.

Given Data / Assumptions:

• Expression skeleton: 9 * 3 * 3 * 3 * 6.
• Each option provides four symbols; the last one is '=' to assert equality to the final number.
• Standard precedence: × and ÷ before + and −.

Concept / Approach:
Interpret each option literally as the four replacements in order. For example, '÷ x - =' gives 9 ÷ 3 × 3 − 3 = 6. Evaluate with precedence (first ÷ and ×), then addition/subtraction, and finally compare both sides.

Step-by-Step Solution:
Using option '÷ x - =': compute left side.9 ÷ 3 = 3; 3 × 3 = 9; 9 − 3 = 6.Thus 6 = 6, the statement is true.

Verification / Alternative check:
Briefly test another option to confirm it fails. For instance, 'x + - =': 9 × 3 + 3 − 3 = 27 + 3 − 3 = 27 ≠ 6.

Why Other Options Are Wrong:

• '+ - x =': 9 + 3 − 3 × 3 = 9 + 3 − 9 = 3 ≠ 6.
• '- + + =': 9 − 3 + 3 + 3 = 12 ≠ 6.
• 'x + - =': 27 + 3 − 3 = 27 ≠ 6.
• 'None of these': not needed because a valid sequence exists.

Common Pitfalls:
Overriding precedence (e.g., doing addition before multiplication) or reading the symbols out of order. Always apply the operators exactly where the asterisks are, in the given order.

Final Answer:
÷ x - =