Difficulty: Medium
Correct Answer: 3, 5
Explanation:
Introduction / Context:
Interchange problems ask which pair of numbers, when swapped, turns a false arithmetic statement into a true one. You must respect operator precedence when reevaluating the expression after each hypothetical swap.
Given Data / Assumptions:
Concept / Approach:
Compute the expression after each candidate swap, honoring ×/÷ precedence. We look for a combination that lands exactly at 38.
Step-by-Step Solution:
Test (3, 5) swap ⇒ 8 × 20 ÷ 5 + 9 − 3.Evaluate: 8 × 20 = 160; 160 ÷ 5 = 32; 32 + 9 = 41; 41 − 3 = 38.Hence the swap (3, 5) makes the equation true.
Verification / Alternative check:
Check a distractor quickly: swap (8, 9) ⇒ 9 × 20 ÷ 3 + 8 − 5 = 60 + 3 = 63, not 38.
Why Other Options Are Wrong:
Common Pitfalls:
Applying operations strictly left-to-right without precedence or swapping a number but forgetting to apply it at both of its original positions if it appears multiple times (here, each appears once).
Final Answer:
3, 5
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