Operator-code puzzle — If x → +, < → −, + → ÷, > → ×, − → =, ÷ → >, = → <, which of the following becomes a true statement?

Introduction / Context:Each printed symbol stands for a different real operator. We must decode each option using the mapping and then test whether the resulting mathematical/relational statement is true.

Given Data / Assumptions:

• Mapping: x→+, <→−, +→÷, >→×, −→=, ÷→>, =→<.
• Standard precedence for × and ÷ over + and −, and relational comparisons applied after arithmetic.

Concept / Approach:Decode token by token, then evaluate LHS and RHS parts around any relation(s).

Step-by-Step Solution:Option C: “5 > 2 + 2 = 10 < 4 x 8” decodes to5 × 2 ÷ 2 < 10 − 4 + 8Left: 5 × 2 ÷ 2 = 5. Right: 10 − 4 + 8 = 14. Hence 5 < 14 is true.Other options decode to false comparisons after evaluation.

Verification / Alternative check:Re-evaluating Option C with strict precedence gives the same result (true); A, B, D evaluate to false.

Why Other Options Are Wrong:They yield contradictions (e.g., Option A decodes to 11 = 0, false).

Common Pitfalls:Applying the mapping twice or forgetting that ÷ maps to the relational ‘>’ in the decoded form.

Final Answer:5 > 2 + 2 = 10 < 4 x 8 is the only true statement after decoding.