Encoded operators and inequalities — choose the true relation: Mapping: A → '+', M → '×', D → '÷', G → '>', L → '<'. Which option is logically correct when decoded and evaluated with standard precedence?

Difficulty: Easy

Correct Answer: 4A 3M 2L 4D 2M 6

Explanation:


Introduction / Context:
We decode each string using the provided mapping for arithmetic and comparison operators, then evaluate both sides with standard precedence to see which inequality is true.


Given Data / Assumptions:

  • A = +, M = ×, D = ÷, G = >, L = <
  • Use ×/÷ before +/− with left-to-right tie-breaking.


Concept / Approach:
Translate and compute each side numerically, then check the indicated comparison ( > or < ). Only one option should produce a true statement.


Step-by-Step Checks (concise):
(a) 4 + 5 ÷ 3 > 6 + 2 × 3 → 5.67 > 12 → false (b) 4 + 5 × 4 < 6 ÷ 2 + 8 → 24 < 11 → false (c) 4 ÷ 2 + 4 > 6 ÷ 2 + 4 → 6 > 7 → false (d) 4 + 3 × 2 < 4 ÷ 2 × 6 → 10 < 12 → true


Why Other Options Are Wrong:
Each computes to a false inequality once decoded and properly evaluated. Typical errors when solving include ignoring precedence or misreading the mapping for M and D.


Common Pitfalls:
Doing addition before finishing ×/÷, or evaluating comparisons before both sides are fully simplified.


Final Answer:
4A 3M 2L 4D 2M 6

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion