Interchanges: swap “+” with “×” and swap the digits 3 ↔ 7 everywhere. Which statement becomes correct after performing both swaps?

Introduction / Context:This is a two-layer transformation puzzle. First interchange the operators “+” and “×”. Second, replace every digit 3 with 7 and every digit 7 with 3 anywhere they occur (on both sides). After applying both swaps, check which equality holds numerically.

Given Data / Assumptions:

• Operator swap: “+” ↔ “×”.
• Digit swap: 3 ↔ 7 in every number (e.g., 23 → 27, 17 → 13, 73 → 37).

Concept / Approach:Transform each option entirely (LHS and RHS), then evaluate the transformed LHS to see whether it equals the transformed RHS.

Step-by-Step Solution:

Verification / Alternative check:Quick checks on other options show mismatches after the two-step swap (e.g., Option A transforms to 27 × 13 + 37 = 388 on LHS but compares with 1241, which does not match).

Why Other Options Are Wrong:

• Their transformed LHS and RHS evaluate to different numbers.

Common Pitfalls:

• Forgetting to swap digits on the RHS as well.
• Applying swaps in the wrong order; here either order still leaves Option D the only true equality.

Final Answer:23 + 17 x 73 = 388