Symbol encoding check — select the correct statement: Encoding: δ → '+', • → '−', γ → '×', η → '÷', ω → '=', β → '>', α → '<'. Which option becomes a true relation after decoding and evaluating with standard precedence?

Introduction / Context:
The problem encodes arithmetic and comparison symbols. After decoding, we evaluate both sides of each candidate with standard precedence and check whether the stated relation is true.

Given Data / Assumptions:

• δ=+, •=−, γ=×, η=÷, ω==, β=>, α=<
• Precedence: ×, ÷ before +, −; left-to-right within the same tier.

Concept / Approach:
Systematically decode each option and compute numerical values on both sides of the relation (either =, >, or <). Exactly one option should hold true.

Step-by-Step Check (true option):
(d) 3 δ 6 • 2 γ 8 η 4 ω 5 → 3 + 6 − 2 × 8 ÷ 4 = 5 Compute ×/÷: 2 × 8 = 16; 16 ÷ 4 = 4 Now +/−: 3 + 6 − 4 = 5 — equality holds

Why Other Options Are Wrong (sketch):
(a) 3×6÷2+8−4 = 13 ≠ 5; (b) 3÷6×2+8−4 = 5 so 5 > 5 is false; (c) 3×6−2+8÷4 = 18, and 18 < 5 is false.

Common Pitfalls:
Misreading ω as > or <, or evaluating +/− before finishing ×/÷ in long strings of operations.

Final Answer:
3 δ 6 • 2 γ 8 η 4 ω 5