IF spectrum occupancy: For a 70 MHz IF carrier with a transponder bandwidth of 36 MHz, between what IF frequencies (in MHz) must the signal energy lie?

Difficulty: Easy

Correct Answer: 52 and 88

Explanation:


Introduction / Context:
In satellite IF processing, the signal must fit within the allocated intermediate-frequency passband. Knowing the allowable lower and upper frequency limits around the IF carrier ensures proper filtering and avoids adjacent-channel interference.



Given Data / Assumptions:

  • Center IF (f_IF) = 70 MHz.
  • Transponder bandwidth B = 36 MHz.
  • Assume symmetric occupancy around the center: ±B/2.


Concept / Approach:

Occupied band edges are at f_IF − B/2 and f_IF + B/2. With B = 36 MHz, B/2 = 18 MHz. Therefore the passband spans 70 − 18 to 70 + 18 MHz.



Step-by-Step Solution:

Compute half-bandwidth: 36/2 = 18 MHz.Lower edge: 70 − 18 = 52 MHz.Upper edge: 70 + 18 = 88 MHz.


Verification / Alternative check:

Filter specifications (e.g., 70 MHz SAW/crystal filters) are commonly centered at 70 MHz with 36 MHz bandwidth, giving exactly 52–88 MHz 3 dB points.



Why Other Options Are Wrong:

  • 34–106 or 34–142: much wider than the stated 36 MHz bandwidth.
  • 106–142: centered at 124 MHz, not 70 MHz.
  • 70–106: not symmetric around 70 and not 36 MHz wide.


Common Pitfalls:

  • Forgetting to divide the bandwidth by 2 when locating band edges around the center frequency.


Final Answer:

52 and 88

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