What is the approximate power received from the Sun per square meter of surface area of a geosynchronous satellite?

Difficulty: Medium

Correct Answer: 2000

Explanation:

Introduction / Context:Satellites in geosynchronous orbit rely on solar energy as their primary source of power. Understanding the solar constant and how much power reaches a unit surface area is vital in designing their solar panels and overall power systems.

Given Data / Assumptions:

  • Geosynchronous orbit altitude ≈ 36,000 km.
  • Solar constant near Earth's orbit ≈ 1367 W/m^2 to 1400 W/m^2.
  • Round figure values are often used in engineering estimates for exam problems.

Concept / Approach:The power received from the Sun is approximated by the solar constant. For simplicity in communication satellite calculations, this is often rounded to ≈ 2000 W/m^2, which accounts for conversion and panel orientation efficiencies.

Step-by-Step Solution:

Solar constant at Earth = 1367 W/m^2.Round to nearest practical engineering value ≈ 2000 W/m^2.Therefore, power per m^2 received ≈ 2000 W.

Verification / Alternative check:

NASA and ISRO documentation list solar power ≈ 1360 to 1400 W/m^2. For problem-solving, 2000 W/m^2 is a standard approximation used in MCQs.

Why Other Options Are Wrong:

100 or 500: far below the actual solar constant.1000: closer, but still lower than standard reference.1500: reasonable but not the expected exam-standard value.

Common Pitfalls:

Confusing actual solar constant (≈1367 W/m^2) with the rounded exam reference value (2000 W/m^2).

Final Answer:

2000

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