Difficulty: Medium
Correct Answer: π(a + b)
Explanation:
Introduction:
Although coax supports a TEM mode without cutoff, higher-order modes (TE/TM) have finite cutoff frequencies. Knowing the TE11 cutoff helps set the upper frequency limit for single-mode coaxial operation.
Given Data / Assumptions:
Concept / Approach:
Analytical solutions give an approximate TE11 cutoff wavelength λc ≈ π(a + b), which is a widely used design rule. Operation should remain well below this cutoff frequency (i.e., at wavelengths ≪ λc) to avoid multimoding.
Step-by-Step Solution:
Verification / Alternative check:
More exact expressions involve solving characteristic equations with Bessel functions; the π(a + b) rule closely tracks the true cutoff and is sufficient for design checks.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing TEM (no cutoff) with TE11 (finite cutoff); the upper frequency limit for single-mode coax is set by TE11.
Final Answer:
π(a + b)
Discussion & Comments