For a very short doublet (electrically short dipole) of length l ≪ λ, the radiation resistance varies with which power of the electrical length? (Let β = 2π/λ; electrical length is β l.)

Difficulty: Easy

Correct Answer: Proportional to (β l)^2

Explanation:


Introduction / Context:
The radiation resistance R_r of an antenna models how effectively it converts current into radiated power. For electrically short dipoles (length much smaller than wavelength), R_r is small and depends strongly on the electrical length.


Given Data / Assumptions:

  • Short dipole (uniform current approximation), l ≪ λ.
  • Electrical length β l where β = 2π/λ.
  • Free-space operation for simplicity.


Concept / Approach:

Classical antenna theory gives R_r ≈ 80 * π^2 * (l/λ)^2 for a short dipole. Since β = 2π/λ, (l/λ)^2 ∝ (β l)^2. Therefore, radiation resistance is proportional to the square of the electrical length, reflecting the weak radiation of very small antennas.


Step-by-Step Solution:

1) Start with R_r ∝ (l/λ)^2 for a short dipole.2) Use β = 2π/λ ⇒ l/λ = (β l)/(2π).3) Hence R_r ∝ (β l)^2.4) Interpret: doubling l (still short) quadruples R_r; halving λ (doubling frequency) also increases R_r.


Verification / Alternative check:

Using the approximate constant: R_r ≈ 80π^2(l/λ)^2 confirms the quadratic dependence and yields numerical values that match measurements for l ≪ λ.


Why Other Options Are Wrong:

  • Linear or square-root dependence and cubic dependence do not match the established short-dipole formula.
  • Independence of β l ignores the small-antenna limit behavior.


Common Pitfalls:

Confusing radiation resistance with input resistance including loss; applying the formula outside the l ≪ λ range.


Final Answer:

Proportional to (β l)^2

More Questions from Microwave Communication

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion