In a rectangular waveguide, which listed mode corresponds to the trivial (non-propagating) solution where all field components are zero?

Difficulty: Easy

Correct Answer: TM00

Explanation:


Introduction / Context:
Waveguide modes are labeled TEmn or TMmn. Not every index pair represents a physical propagating solution. Some index choices lead to a trivial zero-field solution, which is excluded from the set of allowed modes.


Given Data / Assumptions:

  • Hollow rectangular waveguide with perfectly conducting walls (idealized).
  • Mode families: TE and TM with integer indices m, n ≥ 0.
  • Boundary conditions require tangential electric field to vanish at walls.


Concept / Approach:

For TM modes, both tangential electric field components must satisfy standing-wave conditions along the cross-section. If m = n = 0 (TM00), the field solution reduces to zero everywhere to satisfy boundary conditions—hence it is a non-existent (trivial) mode. By contrast, TE10 is the dominant physical mode.


Step-by-Step Solution:

1) Consider TMmn with m or n equal to zero.2) Apply boundary conditions for the scalar potential forms; for m=n=0, fields cannot satisfy non-zero boundary conditions without contradiction.3) Conclude that TM00 implies E = H = 0 (trivial solution), not a propagating mode.4) Therefore, TM00 is excluded from the physical mode set.


Verification / Alternative check:

Standard mode tables omit TM00 for rectangular waveguides; laboratory measurements never observe TM00 propagation.


Why Other Options Are Wrong:

  • TM11, TM01, TM10, TE10: All describe legitimate non-trivial modes with finite cutoff (except TM00).


Common Pitfalls:

Assuming every index pair yields a mode; confusing the TE/TM naming with TEM, which does not propagate in hollow rectangular guides.


Final Answer:

TM00

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