In figure, VEB = 0.6 V, β = 99. Then VC and IC are

• 9.3 V and 1.98 mA respectively
• 4.6 V and 1.98 mA respectively
• 9.3 V and 0.02 mA respectively
• 4.6 V and 0.02 mA respectively

Correct Answer: 9.3 V and 1.98 mA respectively

Explanation:

V_C = 20 - 1.98 x 10^-3 x 5.4 x 10³ ≂ 9.3 V.