Total power in parallel branches: If each of four parallel branches dissipates 1.2 W, what is the total power consumed by the network?

Introduction / Context:
Power in parallel circuits is additive across branches. This question reinforces that total power equals the sum of individual branch powers when all are fed by the same source.

Given Data / Assumptions:

• Number of branches: 4.
• Power dissipated by each branch: 1.2 W.
• All branches operate simultaneously under the same supply.

Concept / Approach:
Total power P_total = Σ P_branch. Since each branch has the same dissipation, multiply the per-branch power by the number of branches.

Step-by-Step Solution:

Verification / Alternative check:
Energy perspective: Over 1 hour, each branch uses 1.2 Wh; four branches use 4.8 Wh. The instantaneous power sum is therefore 4.8 W.

Why Other Options Are Wrong:

• 1.2 W: Only one branch.
• 0.3 W: One quarter of a branch; incorrect scaling.
• 12 W: Tenfold error; would require 3 W per branch.

Common Pitfalls:

• Confusing power addition (add) with resistance/impedance combination rules.

Final Answer:
4.8 W