Curioustab

Home » Electrical Engineering » Parallel Circuits

Five light bulbs are connected in parallel across 110 V. Each bulb is rated at 200 W. The current through each bulb is approximately

2.2 A
137 mA
1.8 A
9.09 A

Correct Answer: 1.8 A

← Previous Question Next Question→

More Questions from Parallel Circuits

Six resistors are in parallel. The two lowest-value resistors are both 1.2 kΩ. The total resistance
If there are a total of 120 mA into a parallel circuit consisting of three branches, and two of the branch currents are 40 mA and 10 mA, the third branch current is
In a certain three-branch parallel circuit, R1 has 12 mA through it, R2 has 15 mA through it, and R3 has 25 mA through it. After measuring a total of 27 mA, you can say that
The following currents are measured in the same direction in a three-branch parallel circuit: 200 mA, 340 mA, and 700 mA. The value of the current into the junction of these branches is
Addition of resistors in parallel increases total resistance and decreases total current.
The total current divides among parallel resistors in a manner directly proportional to the resistance values.
The sum of the currents into a junction is equal to the sum of the currents out of that junction.
A parallel circuit acts as a current divider.
Parallel resistors are connected between the same two points.
The total resistance for two resistors in parallel is equal to the sum of the two resistors.

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion