Node inflow by KCL: In a three-branch parallel circuit, currents of 200 mA, 340 mA, and 700 mA are measured in the same direction into a junction. What is the current into the junction?

Difficulty: Easy

Correct Answer: 1.24 A

Explanation:


Introduction / Context:
Kirchhoff’s Current Law (KCL) also applies when multiple branch currents converge into a node. The total current into the node is the sum of all branch currents directed into that node at that instant.


Given Data / Assumptions:

  • Three measured currents entering the node: 200 mA, 340 mA, 700 mA.
  • All measurements are referenced with the same sign convention (into the node).
  • Steady-state analysis.


Concept / Approach:

Add currents that share the same direction into the node to find the total inflow. This is a direct application of current conservation.


Step-by-Step Solution:

Sum: 200 mA + 340 mA + 700 mA = 1,240 mA.Convert to amperes: 1,240 mA = 1.24 A.Thus, the node inflow is 1.24 A.


Verification / Alternative check:

If the node had only 900 mA entering, the missing 340 mA would violate KCL unless there were an unaccounted source/sink, which the problem does not imply.


Why Other Options Are Wrong:

900 mA and 540 mA are partial sums. 200 mA is just one branch. 0 A contradicts the measurements.


Common Pitfalls:

Forgetting unit conversion mA to A, or accidentally subtracting when all currents share the same direction.


Final Answer:

1.24 A

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