Approximate efficiency of a chopper (DC–DC converter) What is a typical overall efficiency figure for a practical chopper operating under normal conditions?
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A80% or more
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Baround 50%
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Caround 20%
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Daround 5%
Answer
Correct Answer: 80% or more
Explanation
Introduction / Context:DC–DC choppers use high-frequency switching to minimize dissipation and achieve high efficiency. Understanding realistic efficiency helps with thermal design and power budgeting for drives and power supplies.
Given Data / Assumptions:
- Modern switching devices with low conduction and switching losses.
- Reasonable magnetics and minimal control losses.
- No extreme low-load or poorly designed cases.
Concept / Approach:
Losses arise from conduction (I^2R or Vce(sat)·I), switching (overlap and device capacitances), gate drive, magnetics, and ripple. With proper design, these are a small fraction of output power, yielding high efficiency well above 80% and often 90–95% for medium to high power converters.
Step-by-Step Solution:
Estimate conduction loss fraction small with low Rds_on or low Vce(sat).Switching at suitably chosen frequency controls switching loss.Ancillary losses (gate drive, control) are minor at scale.Verification / Alternative check:
Datasheets and application notes routinely report efficiencies exceeding 85–95% under nominal load.
Why Other Options Are Wrong:
- 50%, 20%, 5% are characteristic of linear regulators or faulty designs, not switching choppers.
Common Pitfalls:
Ignoring cooling and layout; excessive switching frequency without need; operating deep in light-load where fixed overheads dominate can reduce efficiency but rarely to very low values.
Final Answer:
80% or more