Input voltage vs input current waveshape in a single-phase semiconverter (R load) For a single-phase semiconverter supplying a purely resistive load, under what condition are the input voltage and input current waveshapes similar?

Introduction / Context:Power-factor and harmonic performance in controlled rectifiers are tied to how closely input current follows the input voltage. With resistive loads, conduction intervals depend on firing angle.

Given Data / Assumptions:

• Singe-phase semiconverter (half-controlled bridge).
• Pure R load, no supply inductance.
• We compare shapes of source voltage and source current.

Concept / Approach:With an R load, current is proportional to instantaneous output voltage during conduction. If α = 0°, conduction occurs during the positive half-cycle similar to a diode rectifier, giving a current waveform that mirrors the voltage half-cycle. For α > 0°, conduction begins later, so current is phase-delayed and truncated, no longer matching the voltage shape.

Step-by-Step Solution:Set α = 0° → output equals the positive half-cycle of input → current is a half-sine in phase.Increase α → conduction shifts and shortens; waveform differs from the input voltage.Hence, similarity occurs only at α = 0°.

Verification / Alternative check:Drawing input current for α = 0° shows an in-phase half-sine. For α = 30° or 60°, the current duration and phase shift clearly differ.

Why Other Options Are Wrong:Always/Never: Too absolute; α determines similarity.High α: Produces shorter, delayed conduction—not similar.

Common Pitfalls:Assuming R-load guarantees shape similarity; the firing angle changes conduction timing.

Final Answer:similar only if firing angle α = 0°