Difficulty: Medium
Correct Answer: ΔV = ω L I0
Explanation:
Introduction / Context:Finite source inductance causes overlap between outgoing and incoming devices during commutation. This overlap reduces the average output voltage, an essential correction for accurate design.
Given Data / Assumptions:
Concept / Approach:During overlap, part of the supply voltage is dropped across the source inductance while current transfers, reducing the voltage presented to the DC side. For single-phase bridges the well-known reduction is ΔV = ω L I0.
Step-by-Step Solution:Inductive drop during overlap ≈ L di/dt; with constant I0 transfer over electrical angle → equivalent average drop equals ω L I0.Hence, Vdc_actual = Vdc_ideal − ω L I0.
Verification / Alternative check:Detailed derivations integrating instantaneous supply minus inductive drop over the conduction interval yield the same compact correction term for small overlap.
Why Other Options Are Wrong:Scaled variants (2, π, 1/π): Do not match standard single-phase result.Zero: Ignores real commutation effects of source inductance.
Common Pitfalls:Confusing single-phase with three-phase results where coefficients differ; also forgetting that I0 must be essentially constant for this simple form.
Final Answer:ΔV = ω L I0
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