Memory technologies – identifying how dynamic RAM (DRAM) stores one bit In dynamic semiconductor memory (DRAM), a single data bit is stored as charge on which circuit element?

Difficulty: Easy

Correct Answer: capacitor

Explanation:


Introduction / Context:
This item checks core memory-technology knowledge: how dynamic random-access memory (DRAM) represents a single binary bit. Understanding the storage element explains why DRAM needs periodic refresh and how it differs from static RAM (SRAM) and register flip-flops.


Given Data / Assumptions:

  • The device class is DRAM (dynamic RAM).
  • We are considering the physical circuit element that retains a 0 or 1.
  • Binary information is represented by the presence or absence of electric charge.


Concept / Approach:
In DRAM, each cell pairs a MOS access transistor with a tiny capacitor. A stored 1 corresponds to charge on the capacitor; a 0 corresponds to little or no charge. Because the charge leaks over time, DRAM must be refreshed periodically. This is fundamentally different from SRAM, which uses cross-coupled inverters (flip-flop like) to hold state as long as power is applied.


Step-by-Step Solution:

Identify the technology: DRAM uses charge storage, not latch feedback.Determine the element that stores charge: the capacitor is the storage device.Conclude that the correct answer is the capacitor.


Verification / Alternative check:
Any DRAM cell schematic shows a single transistor connected to a storage capacitor; refresh specifications in datasheets further confirm charge-based storage.


Why Other Options Are Wrong:

  • Diode: Not used as the storage element in DRAM cells.
  • Resistor: Not the charge-holding component; resistors conduct but do not store charge like capacitors.
  • Flip-flop: Flip-flops are used in SRAM/registers; DRAM does not use a bistable latch per bit.


Common Pitfalls:

  • Confusing DRAM with SRAM and assuming a latch stores the bit.
  • Overlooking the need for refresh, which is a direct consequence of capacitor leakage.


Final Answer:
capacitor

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion