If one root of the quadratic equation 2x ² + Px + 4 = 0 is 2, find the second root and value of P.

According to given question , we have
?. x³ - 371 = 629
? x = ?1000 = 10
?. y³ - 543 = 788
? y = ?1331 = 11
From above both equations it is clear that x < y is correct answer .

From the given equations , we know that
?. x² - 1 = 0
? x² = 1
? x = ± ?1 = ± 1
?. y² + 4y + 3 = 0
? y² + y + 3y + 3 = 0
? y( y + 1) + 3( y + 1) = 0
? ( y + 1) ( y + 3)
? y = -3 or -1
From above equations it is clear that x ? y is correct answer .

According to question ,we can say that
From equation ?. x⁴ = 398 + 227 = 625
? x⁴ = 5⁴

From equation ?. y² = 346 - 321 = 25
? y² = 5²

From the given equations , we can say that
From equation ?.
x² - 7x + 12 = 0
? x² - 4x - 3x + 12 = 0
? x( x - 4 ) - 3( x - 4 ) = 0
? ( x - 3 )( x - 4 ) = 0
? x = 3 or x = 4

From equation ?.
y² + y - 12 = 0
? y² + 4y - 3y - 12 = 0
? y( y + 4 ) - 3( y + 4 ) = 0
? ( y - 3 )( y + 4 ) = 0
? y = 3 or y = - 4
From above both equations it is clear that x ? y is correct answer .

We can say that ,
The given quadratic equation x² ? 6x + 5 = 0 ? ( x - 5 )( x - 1 ) = 0 ? x = 5 or 1
Now , | x - 3 | = 2 ? ( x - 3 ) = 2 or - ( x - 3 ) = 2 ? x = 3 + 2 = 5 or x = 3 - 2 = 1
? x² - 6x + 5 = 0 and | x - 3 | = 2 are equivalent.