The average of four positive integers is 73.5. The highest integer is 108 and the lowest integer is 29, the difference between the remaining two integers is 15. Which of the following is the smaller of the remaining two integers?

If two equal distance are covered at different speeds at A km/h and B km/h respectively, then
Average speed during the whole journey = 2AB/(A + B) km/h

? Average speed of the car = (2 x 42 x 48) / (42 + 48)
= (2 x 42 x 48)/90
= 44.8 km/h

Here n = 120, a = 35, x = 39, y = 15
Number of students passed = n (a - y)/(x - y)
= 120(35 - 15)/(39 -15)
= 100 students passed

Given that, number of boys (n₁) = 15
Numbers of girls (n₂)= 10
Average weight of boys and girls = 38.4 kg
Average of boys = 40 kg
Let average of girls be a₂
By formula, average = (na₁ + n₂ a₂) / (n₁ + n₂)
? 38.4 = (15(40) + 10 x a₂)/(15 + 10)
? 38.4 x 25 = 600+ 10a₂
? a₂= (960 - 600)/10 = 360/10 = 36 kg

Here, n₁ = 5, n₂ = 10, n₃ = 15, a₁ = 25, a₂ = 50, a₃ = 35
According to the formula,
Average price = (n₁a₁ + n₂a₂ + n₃a₃) / (n₁ + n₂ + n₃)
= (5 x 25 + 10 x 50 + 15 x 35) / (5 + 10 + 15)
= (25 + 100 + 105) / (1 + 2 + 3)
= 230/6
= ? 38.33

Let The total number of workers = N
According To the question,
60N = 12 x 400 + 56 (N - 12)
? 60N - 56N = 4800 - 672
? 4N = 4128
? N = 1032

Let average of a inning = x
Total runs = 9x
According to the question,
(9x + 100) /10 = x + 8
? 9x + 100 = 10x + 80
x = 20
Average after 10 inning = 20 + 8 = 28

Total age of 5 memeber (3 yr ago) = 27 x 5 = 135 yr
Total age of 5 members (at present) = 135 + 5 x 3 = 150 yr.
Let the persent age of child = x
? 27 = (150 + x)/6
? x = 162 - 150 = 12 yr.

Total age of all three boys
= 3 x 15 = 45 yr
Ratio of ages = 3 : 5 : 7
? Age of the oldest boy
= [7/(3 + 5 + 7)] x 45 = (7/15) x 45 = 21 yr

Let average expenditure of 9 persons = x.
According to the question,
12 x 8 + (x + 16) = 9x
? 8x = 112
? x = 112/8 = 14
? Total money spent = 9x = 9 x 14 = ? 126

Let the number of papers = x.
According to the question,
64x + 18 + 4 = 66x
? 2x = 22
? x = 22/2 = 11