Backdating family averages: The present average age of a 4-member family is 20 years. The youngest is 4 years old now. What was the average age of the family at the time of the youngest's birth (i.e., 4 years ago, before the baby was counted)?

Difficulty: Medium

Correct Answer: 21 1/3 yr

Explanation:


Introduction / Context:
This problem asks for the average at the time of the youngest child’s birth, when only the three older members were counted. We must backdate ages by 4 years for those three and exclude the newborn (age 0 then).


Given Data / Assumptions:

  • Current average (4 members) = 20 → current total = 80
  • Youngest current age = 4 → youngest was 0 at birth
  • At birth time: only 3 members are counted


Concept / Approach:
Four years ago, the three older members were each 4 years younger. Subtract 4 for each of those three from the current total, exclude the youngest (who was 0 then), and divide by 3.


Step-by-Step Solution:

Current total (all 4) = 80Remove youngest now to isolate three older = 80 - 4 = 76Backdate 4 years for each of the three: subtract 3 * 4 = 12Total of three at birth time = 76 - 12 = 64Average then = 64 / 3 = 21 1/3 years


Verification / Alternative check:
If we included the newborn at age 0 and divided by 4, we would get 16, but the question clarifies “before the baby was counted,” so use 3 members, giving 21 1/3.


Why Other Options Are Wrong:

  • 27, 22: do not match the correctly backdated total for three members.
  • 23 1/3: overestimates the average.
  • 16: corresponds to including the newborn at age 0, which the prompt excludes.


Common Pitfalls:
Including the newborn in the average four years ago (age 0) or forgetting to reduce each older member by 4 years when backdating.


Final Answer:
21 1/3 yr

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