The average age of 5 member of a family is 25 yr. If the servant of the family is included the average age increased by 40% .What is the age of servant?

Let the number of students in the class = N
According to the question,
(35N + 6 x 33) / (N + 6) = 35 - (1/2)
? 35N + 198 = 34.5 (N + 6)
? 35N +198 = 34.5N + 207
? 0.5N = 207 -198N = 9/0.5 = 18
? N = 18 days

Sum of 14 girls and teacher age = 15 x 15 = 225
Without teacher's age sum of 14 girls age = 14 x 14 = 196
? Teacher's age = 225 -196 = 29 year

Here, n = 21, a = 64, b = 65
Weight of teacher = n(b - a) + b
= 21( 65 - 64) + 65
= 21 + 65
= 86 kg

Here n= 34, a = 42 and b = 42.4
Weight of the teacher.
= n(b -a) + b
= 34 ( 42.4 - 42) + 42.4
= 13.6 + 42.4 = 56.0 kg

Here, n = 10, a = 60, b = 62
Number of runs scored in 11th inning
= n (b - a) + b
= 10 (62 - 60) + 62
= 20 + 62 = 82

Here, average decreases by 3 months of 3/12 yr.
Sum of ages decreased
= 30 x 3/12 = 15/2 = 7.5 yr
? Age of priyanka = (25 - 7.5) = 17.5 yr.

Temperature of (Mon + Tue + Wed) = 37 x 3 = 11°C

Temperature of (Tue + Wed + Thu) = 34 x 3 = 102°C

Temperature of (Mon - Thu) = 111°C - 102°C = 9°C

Temperature of [Mon - 4/5(Mon] = 9
Temperature of Monday = 9 x 5 = 45°C

? Temperature of Thursday = 45 x 4/5 = 36°C

Sum of 11 numbers = 36 x 11 = 396
Sum of 9 numbers = 34 x 9 = 306
Sum of remaining two numbers =396 - 306 = 90
? The smaller number = (2 x 90)/(2 + 3) = 180/5 = 36

Let the 5 consecutive positive integers be x + 1, x + 3, x + 5, x + 7, x + 9
Average = (Sum of all terms) / (Number of terms)
⇒ 9 = [(x + 1) + (x + 3) + (x + 5) + (x + 7) + (x + 9)]/5
⇒ 9 = (5x +25)/5
⇒ 45 = 5x + 25
⇒ 5x = 45 - 25
∴ 5x = 20 ⇒ x = 4
The least one is x + 1 = 4 + 1 = 5

According to the question,
70m + 91n = 80 (m + n)
⇒ 70m + 91n = 80m + 80n
⇒ 10m = 11n
⇒ n/m = 10/11