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- Question
Point out the error in the program?
typedef struct data mystruct; struct data { int x; mystruct *b; };
Options- A. Error: in structure declaration
- B. Linker Error
- C. No Error
- D. None of above
- Correct Answer
- No Error
ExplanationHere the type name mystruct is known at the point of declaring the structure, as it is already defined. - 1. What will be the output of the program?
#include<stdio.h> int main() { enum status {pass, fail, absent}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = absent; stud3 = fail; printf("%d %d %d\n", stud1, stud2, stud3); return 0; }
Options- A. 0, 1, 2
- B. 1, 2, 3
- C. 0, 2, 1
- D. 1, 3, 2 Discuss
- 2. What will be the output of the program in Turbo C (under DOS)?
#include<stdio.h> int main() { struct emp { char *n; int age; }; struct emp e1 = {"Dravid", 23}; struct emp e2 = e1; strupr(e2.n); printf("%s\n", e1.n); return 0; }
Options- A. Error: Invalid structure assignment
- B. DRAVID
- C. Dravid
- D. No output Discuss
- 3. What will be the output of the program?
#include<stdio.h> int main() { struct byte { int one:1; }; struct byte var = {1}; printf("%d\n", var.one); return 0; }
Options- A. 1
- B. -1
- C. 0
- D. Error Discuss
- 4. What will be the output of the program?
#include<stdio.h> int main() { enum days {MON=-1, TUE, WED=6, THU, FRI, SAT}; printf("%d, %d, %d, %d, %d, %d\n", MON, TUE, WED, THU, FRI, SAT); return 0; }
Options- A. -1, 0, 1, 2, 3, 4
- B. -1, 2, 6, 3, 4, 5
- C. -1, 0, 6, 2, 3, 4
- D. -1, 0, 6, 7, 8, 9 Discuss
- 5. What will be the output of the program?
#include<stdio.h> int main() { struct value { int bit1:1; int bit3:4; int bit4:4; }bit={1, 2, 13}; printf("%d, %d, %d\n", bit.bit1, bit.bit3, bit.bit4); return 0; }
Options- A. 1, 2, 13
- B. 1, 4, 4
- C. -1, 2, -3
- D. -1, -2, -13 Discuss
- 6. Point out the error in the program?
struct emp { int ecode; struct emp e; };
Options- A. Error: in structure declaration
- B. Linker Error
- C. No Error
- D. None of above Discuss
- 7. Point out the error in the program?
#include<stdio.h> int main() { union a { int i; char ch[2]; }; union a z1 = {512}; union a z2 = {0, 2}; return 0; }
Options- A. Error: invalid union declaration
- B. Error: in Initializing z2
- C. No error
- D. None of above Discuss
- 8. Point out the error in the program?
#include<stdio.h> int main() { struct bits { float f:2; }bit; printf("%d\n", sizeof(bit)); return 0; }
Options- A. 4
- B. 2
- C. Error: cannot set bit field for float
- D. Error: Invalid member access in structure Discuss
- 9. Point out the error in the program?
#include<stdio.h> int main() { struct emp { char name[20]; float sal; }; struct emp e[10]; int i; for(i=0; i<=9; i++) scanf("%s %f", e[i].name, &e[i].sal); return 0; }
Options- A. Error: invalid structure member
- B. Error: Floating point formats not linked
- C. No error
- D. None of above Discuss
- 10. Point out the error in the program?
#include<stdio.h> int main() { struct emp { char n[20]; int age; }; struct emp e1 = {"Dravid", 23}; struct emp e2 = e1; if(e1 == e2) printf("The structure are equal"); return 0; }
Options- A. Prints: The structure are equal
- B. Error: Structure cannot be compared using '=='
- C. No output
- D. None of above Discuss
Structures, Unions, Enums problems
Search Results
Correct Answer: 0, 2, 1
Correct Answer: DRAVID
Correct Answer: -1
Correct Answer: -1, 0, 6, 7, 8, 9
Correct Answer: -1, 2, -3
Explanation:
Note the below statement inside the struct:
int bit1:1; --> 'int' indicates that it is a SIGNED integer.
For signed integers the leftmost bit will be taken for +/- sign.
If you store 1 in 1-bit field:
The left most bit is 1, so the system will treat the value as negative number.
The 2's complement method is used by the system to handle the negative values.
Therefore, the data stored is 1. The 2's complement of 1 is also 1 (negative).
Therefore -1 is printed.
If you store 2 in 4-bits field:
Binary 2: 0010 (left most bit is 0, so system will treat it as positive value)
0010 is 2
Therefore 2 is printed.
If you store 13 in 4-bits field:
Binary 13: 1101 (left most bit is 1, so system will treat it as negative value)
Find 2's complement of 1101:
1's complement of 1101 : 0010
2's complement of 1101 : 0011 (Add 1 to the result of 1's complement)
0011 is 3 (but negative value)
Therefore -3 is printed.
int bit1:1; --> 'int' indicates that it is a SIGNED integer.
For signed integers the leftmost bit will be taken for +/- sign.
If you store 1 in 1-bit field:
The left most bit is 1, so the system will treat the value as negative number.
The 2's complement method is used by the system to handle the negative values.
Therefore, the data stored is 1. The 2's complement of 1 is also 1 (negative).
Therefore -1 is printed.
If you store 2 in 4-bits field:
Binary 2: 0010 (left most bit is 0, so system will treat it as positive value)
0010 is 2
Therefore 2 is printed.
If you store 13 in 4-bits field:
Binary 13: 1101 (left most bit is 1, so system will treat it as negative value)
Find 2's complement of 1101:
1's complement of 1101 : 0010
2's complement of 1101 : 0011 (Add 1 to the result of 1's complement)
0011 is 3 (but negative value)
Therefore -3 is printed.
Correct Answer: Error: in structure declaration
Explanation:
The structure
emp contains a member
e of the same type.(i.e)
struct emp. At this stage compiler does not know the size of sttructure.
Correct Answer: Error: in Initializing z2
Correct Answer: Error: cannot set bit field for float
Correct Answer: Error: Floating point formats not linked
Explanation:
At run time it will show an error then program will be terminated.
Sample output: Turbo C (Windows)
c:\>myprogram
Sample
12.123
scanf : floating point formats not linked
Abnormal program termination
Correct Answer: Error: Structure cannot be compared using '=='
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