Memory Allocation problems
- 1. What will be the output of the program?
#include<stdio.h> #include<string.h> int main() { char *s; char *fun(); s = fun(); printf("%s\n", s); return 0; } char *fun() { char buffer[30]; strcpy(buffer, "RAM"); return (buffer); }
Options- A. 0xffff
- B. Garbage value
- C. 0xffee
- D. Error Discuss
Correct Answer: Garbage value
Explanation:
The output is unpredictable since
buffer is an auto array and will die when the control go back to
main. Thus
s will be pointing to an array , which not exists.
- 2. How many bytes of memory will the following code reserve?
#include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf("Allocation failed"); return 0; }
Options- A. 65536
- B. Allocation failed
- C. Error
- D. No output Discuss
Correct Answer: Allocation failed
Explanation:
Hence 256*256 = 65536 is passed to malloc() function which can allocate upto 65535. So the memory allocation will be failed in 16 bit platform (Turbo C in DOS).
If you compile the same program in 32 bit platform like Linux (GCC Compiler) it may allocate the required memory.
- 3. What will be the output of the program?
#include<stdio.h> #include<stdlib.h> int main() { union test { int i; float f; char c; }; union test *t; t = (union test *)malloc(sizeof(union test)); t->f = 10.10f; printf("%f", t->f); return 0; }
Options- A. 10
- B. Garbage value
- C. 10.100000
- D. Error Discuss
Correct Answer: 10.100000
- 4. What will be the output of the program (16-bit platform)?
#include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(20); printf("%d\n", sizeof(p)); free(p); return 0; }
Options- A. 4
- B. 2
- C. 8
- D. Garbage value Discuss
Correct Answer: 2
- 5. What will be the output of the program?
#include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(20); /* Assume p has address of 1314 */ free(p); printf("%u", p); return 0; }
Options- A. 1314
- B. Garbage value
- C. 1316
- D. Random address Discuss
Correct Answer: 1314
- 6. Assume integer is 2 bytes wide. What will be the output of the following code?
#include<stdio.h> #include<stdlib.h> #define MAXROW 3 #define MAXCOL 4 int main() { int (*p)[MAXCOL]; p = (int (*) [MAXCOL])malloc(MAXROW *sizeof(*p)); printf("%d, %d\n", sizeof(p), sizeof(*p)); return 0; }
Options- A. 2, 8
- B. 4, 16
- C. 8, 24
- D. 16, 32 Discuss
Correct Answer: 2, 8
- 7. Assume integer is 2 bytes wide. How many bytes will be allocated for the following code?
#include<stdio.h> #include<stdlib.h> #define MAXROW 3 #define MAXCOL 4 int main() { int (*p)[MAXCOL]; p = (int (*) [MAXCOL])malloc(MAXROW *sizeof(*p)); return 0; }
Options- A. 56 bytes
- B. 128 bytes
- C. 24 bytes
- D. 12 bytes Discuss
Correct Answer: 24 bytes
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