#include<stdio.h> #define MAX 128 int main() { char mybuf[] = "India"; char yourbuf[] = "CURIOUSTAB"; char *const ptr = mybuf; *ptr = 'a'; ptr = yourbuf; return 0; }
Step 2: char yourbuf[] = "CURIOUSTAB"; The variable yourbuf is declared as an array of characters and initialized with string "CURIOUSTAB".
Step 3: char *const ptr = mybuf; Here, ptr is a constant pointer, which points at a char.
The value at which ptr it points is not a constant; it will not be an error to modify the pointed character; There will be an error only to modify the pointer itself.
Step 4: *ptr = 'a'; The value of ptr is assigned to 'a'.
Step 5: ptr = yourbuf; Here, we are changing the pointer itself, this will result in the error "cannot modify a const object".
#include<stdio.h> int main(int argc, char *argv, char *env[]) { int i; for(i=1; i<argc; i++) printf("%s\n", env[i]); return 0; }
#include<stdio.h> int fun(int, int); typedef int (*pf) (int, int); int proc(pf, int, int); int main() { printf("%d\n", proc(fun, 6, 6)); return 0; } int fun(int a, int b) { return (a==b); } int proc(pf p, int a, int b) { return ((*p)(a, b)); }
#include<stdio.h> int main() { int *j; void fun(int**); fun(&j); return 0; } void fun(int **k) { int a=10; /* Add a statement here */ }
/* sample.c */ #include<stdio.h> int main(int argc, char *argv[]) { int i=0; i+=strlen(argv[1]); while(i>0) { printf("%c", argv[1][--i]); } return 0; }
struct emp { int ecode; struct emp *e; };
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