Floating Point Issues problems
- 1. If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?
#include<stdio.h> #include<math.h> int main() { float a=5.375; char *p; int i; p = (char*)&a; for(i=0; i<=3; i++) printf("%02x\n", (unsigned char)p[i]); return 0; }
Options- A. 40 AC 00 00
- B. 04 CA 00 00
- C. 00 00 AC 40
- D. 00 00 CA 04 Discuss
Correct Answer: 00 00 AC 40
- 2. What will you do to treat the constant 3.14 as a long double?
Options- A. use 3.14LD
- B. use 3.14L
- C. use 3.14DL
- D. use 3.14LF Discuss
Correct Answer: use 3.14L
Explanation:
Given 3.14 is a double constant.
To specify 3.14 as long double, we have to add L to the 3.14. (i.e 3.14L)
- 3. What will you do to treat the constant 3.14 as a float?
Options- A. use float(3.14f)
- B. use 3.14f
- C. use f(3.14)
- D. use (f)(3.14) Discuss
Correct Answer: use 3.14f
Explanation:
Given 3.14 is a double constant.
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)
- 4. The binary equivalent of 5.375 is
Options- A. 101.101110111
- B. 101.011
- C. 101011
- D. None of above Discuss
Correct Answer: 101.011
- 5. We want to round off x, a float, to an int value, The correct way to do is
Options- A. y = (int)(x + 0.5)
- B. y = int(x + 0.5)
- C. y = (int)x + 0.5
- D. y = (int)((int)x + 0.5) Discuss
Correct Answer: y = (int)(x + 0.5)
Explanation:
Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.
y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)
Example:
#include <stdio.h>
int main ()
{
float x = 3.6;
int y = (int)(x + 0.5);
printf ("Result = %d\n", y );
return 0;
}
Output:
Result = 4.
- 6. Which of the following statement obtains the remainder on dividing 5.5 by 1.3?
Options- A. rem = (5.5 % 1.3)
- B. rem = modf(5.5, 1.3)
- C. rem = fmod(5.5, 1.3)
- D. Error: we can't divide Discuss
Correct Answer: rem = fmod(5.5, 1.3)
Explanation:
fmod(x,y) - Calculates x modulo y, the remainder of x/y.
This function is the same as the modulus operator. But fmod() performs floating point divisions.
This function is the same as the modulus operator. But fmod() performs floating point divisions.
Example:
#include <stdio.h>
#include <math.h>
int main ()
{
printf ("fmod of 5.5 by 1.3 is %lf\n", fmod (5.5, 1.3) );
return 0;
}
Output:
fmod of 5.5 by 1.3 is 0.300000
- 7. Which of the following range is a valid long double (Turbo C in 16 bit DOS OS)?
Options- A. 3.4E-4932 to 1.1E+4932
- B. 3.4E-4932 to 3.4E+4932
- C. 1.1E-4932 to 1.1E+4932
- D. 1.7E-4932 to 1.7E+4932 Discuss
Correct Answer: 3.4E-4932 to 1.1E+4932
Explanation:
The range of long double is 3.4E-4932 to 1.1E+4932
- 8. A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?
Options- A. ABCD
- B. DCBA
- C. 0xABCD
- D. Depends on big endian or little endian architecture Discuss
Correct Answer: Depends on big endian or little endian architecture
- 9. Which statement will you add in the following program to work it correctly?
#include<stdio.h> int main() { printf("%f\n", log(36.0)); return 0; }
Options- A. #include<conio.h>
- B. #include<math.h>
- C. #include<stdlib.h>
- D. #include<dos.h> Discuss
Correct Answer: #include<math.h>
Explanation:
math.h is a header file in the standard library of C programming language designed for basic mathematical operations.
Declaration syntax: double log(double);
- 10. What are the different types of real data type in C?
Options- A. float, double
- B. short int, double, long int
- C. float, double, long double
- D. double, long int, float Discuss
Correct Answer: float, double, long double
Explanation:
The floating point data types are called real data types. Hence
float,
double, and
long double are real data types.
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