Thermal Energy Scale at Room Temperature If k is Boltzmann’s constant and T is absolute temperature, what is the approximate value of kT (in electronvolts) at room temperature (≈ 300 K)?

Difficulty: Easy

Correct Answer: kT ≈ 0.025 eV

Explanation:


Introduction / Context:
The product kT sets a natural thermal energy scale and appears throughout semiconductor physics, statistical mechanics, and device modeling. Knowing its approximate value at room temperature is essential for estimating carrier distributions, reaction rates, and noise levels without a calculator.


Given Data / Assumptions:

  • k = 8.617 × 10^-5 eV/K (Boltzmann’s constant in eV/K).
  • Room temperature T ≈ 300 K.
  • Order-of-magnitude estimate suffices.


Concept / Approach:

Compute kT directly using the eV-based constant. This avoids unit conversions and gives an immediate sense of energy scales relevant to bandgaps, activation energies, and thermal noise.


Step-by-Step Solution:

Use k = 8.617 × 10^-5 eV/K.Compute kT = 8.617 × 10^-5 * 300 ≈ 2.585 × 10^-2 eV.Round: kT ≈ 0.026 eV, commonly quoted as ≈ 0.025 eV.


Verification / Alternative check:

Using SI form (k = 1.381 × 10^-23 J/K) and 1 eV = 1.602 × 10^-19 J gives the same result, confirming consistency.


Why Other Options Are Wrong:

  • 0.5 eV and 1 eV are too large by factors of 20–40; 100 eV is entirely off the scale for thermal energies at 300 K.


Common Pitfalls:

Mixing Kelvin and Celsius; forgetting the eV/K value of Boltzmann’s constant.


Final Answer:

kT ≈ 0.025 eV

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