The hexadecimal equivalent of 15,536 is ________. 3CB0 3C66 63C0 6300

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Question
The hexadecimal equivalent of 15,536 is ________.
Options
A. 3CB0
B. 3C66
C. 63C0
D. 6300

Correct Answer

3CB0

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1. List the state of each output pin of a 7447 if RBI = 0, LT = 1, A₀ = 1, A₁ = 0, A₂ = 0, and A₃ = 1.
Options
A. RBO = 0, a = 0, b = 0, c = 0, d = 1, e = 1, f = 0, g = 0
B. RBO = 1, a = 0, b = 0, c = 0, d = 1, e = 1, f = 0, g = 0
C. RBO = 0, a = 0, b = 0, c = 0, d = 0, e = 1, f = 0, g = 0
D. RBO = 1, a = 0, b = 0, c = 0, d = 0, e = 1, f = 0, g = 0

2. What is the difference between a 7490 and a 7492?
Options
A. 7490 is a MOD-12, 7492 is a MOD-10
B. 7490 is a MOD-12, 7492 is a MOD-16
C. 7490 is a MOD-16, 7492 is a MOD-10
D. 7490 is a MOD-10, 7492 is a MOD-12

4. The toggle condition in a master-slave J-K flip-flop means that Q and will switch to their ________ state(s) at the ________.
Options
A. opposite, active clock edge
B. inverted, positive clock edge
C. quiescent, negative clock edge
D. reset, synchronous clock edge

9. For a one-shot application, how can HDL code be used to make a circuit respond once to each positive transition on its trigger input?
Options
A. By using a counter
B. By using an active clock
C. By using an immediate reload
D. By using edge trapping

10. One of the major drawbacks to the use of asynchronous counters is:
Options
A. low-frequency applications are limited because of internal propagation delays
B. high-frequency applications are limited because of internal propagation delays
C. asynchronous counters do not have major drawbacks and are suitable for use in high- and low-frequency counting applications
D. asynchronous counters do not have propagation delays and this limits their use in high-frequency applications

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