If a 10-bit ring counter has an initial state 1101000000, what is the state afte

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Question
If a 10-bit ring counter has an initial state 1101000000, what is the state after the second clock pulse?
Options
A. 1101000000
B. 0011010000
C. 1100000000
D. 0000000000

Correct Answer

0011010000

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1. The bit sequence 0010 is serially entered (right-most bit first) into a 4-bit parallel out shift register that is initially clear. What are the Q outputs after two clock pulses?
Options
A. 0000
B. 0010
C. 1000
D. 1111

2. A bidirectional 4-bit shift register is storing the nibble 1110. Its input is LOW. The nibble 0111 is waiting to be entered on the serial data-input line. After two clock pulses, the shift register is storing ________.
Options
A. 1110
B. 0111
C. 1000
D. 1001

4. A bidirectional 4-bit shift register is storing the nibble 1101. Its input is HIGH. The nibble 1011 is waiting to be entered on the serial data-input line. After three clock pulses, the shift register is storing ________.
Options
A. 1101
B. 0111
C. 0001
D. 1110

7. How would a latch circuit be used in a microprocessor system?
Options
A. as transportation for Intel employees
B. for a group of data that is the same
C. as a set of common connections for transfer of data

9. When is it important to use a three-state buffer?
Options
A. when two or more outputs are connected to the same input
B. when all outputs are normally HIGH
C. when all outputs are normally LOW
D. when two or more outputs are connected to two or more inputs

10. When the output of a tristate shift register is disabled, the output level is placed in a:
Options
A. float state
B. LOW state
C. high-impedance state
D. float or high-impedance state

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