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A TV picture is to be transmitted over a channel of 6 MHz bandwidth at a 35 dB S/N ratio. The capacity of the channel is

Q: A TV picture is to be transmitted over a channel of 6 MHz bandwidth at a 35 dB S/N ratio. The capacity of the channel is

W = B = Bandwidth C = 6 x 106 x 12 = 72 Mbps.

50 Mbps
100 Mbps
36 Mbps
72 Mbps

Correct Answer: 72 Mbps

Explanation:

W = B = Bandwidth

C = 6 x 10⁶ x 12 = 72 Mbps.

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