A TV picture is to be transmitted over a channel of 6 MHz bandwidth at a 35 dB S/N ratio. The capacity of the channel is

Amplitude = .

.

Since y is at logic '1' initially, y' must be at logic '1'.

Also, one input of the EXOR gate is tied to zero therefore 'f' will be directly transferred to the output.

The logic gates will introduce gate delays which will lead to the answer .

Mobility of electrons

m = 2.5 for electrons and 2.7 for holes in Si.

A quantity of any substance equal to its molecular weight in grams is a mole of that substance contains the same number of molecules as one mole of any other substance. This Avogadro's number and equals 6.02 x 10²³ molecules per mole. Thus

= 9.03 x 10²⁸ electrons/m³

Since for tungsten the atomic and the molecular weights are the same. Therefore for tungsten

E_F = 3.64 x 10^-19(?)^2/3

= 3.64 x 10^{- 19}(9.03 x 10²⁸)^2/3

E_F = 7.326 eV.

(s³ + 2s² + 5s + 6)y(s) = (s² + 4) x (s)

s³y(s) + 2s²y(s) + 5sy(s) + 6y(s) = s² x (s) + 4 x (s)

Replacing s by and y(s) by y(t) and x(s) by x(t) we get

y(t) + 2y(t) + 5y(t) + 6y(t)

= x(t) + 4x(t)

+ 2 + 5 + 6 = + 4x

This is required differential equation.

E_max - E_min = 0.5 x 1 kV = 0.5 kV

2E_max = 1.5 kVi, E_max = 0.75 kV

E_min = 0.25 kV.

?

? = - 8V_P - 16

? + 8V_P + 16 = 0

? (V_P + 4)² = 0

? V_P = -4 V.

(C) is without over modulation.

V_T(new) = V_T(odd) +

= 6.903 x 10^-8

?

?

f_B = - 8.6 x 10¹¹

The threshold voltage is always negative for p-channel and hence implant is of p-type.