A n-channel JFET has IDSS = 2 mA, Gate to source voltage VGS = - 2 V and trans-conductance is 0.5 mW then pinch-off voltage is __________ .

• - 2 V
• 2 V
• - 4 V
• 4 V

Correct Answer: - 4 V

Explanation:

∴

∴ = - 8V_P - 16

∴ + 8V_P + 16 = 0

∴ (V_P + 4)² = 0

∴ V_P = -4 V.