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A n-channel JFET has IDSS = 2 mA, Gate to source voltage VGS = - 2 V and trans-conductance is 0.5 mW then pinch-off voltage is __________ .

Correct Answer: - 4 V

Explanation:




= - 8VP - 16


+ 8VP + 16 = 0


(VP + 4)2 = 0


VP = -4 V.


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