Suppose that the modulating signal is m(t) = 2cos (2pfmt) and the carrier signal is xC(t) = AC cos(2pfct), which one of the following is a conventional AM signal without over modulation?

• x(t) = Acm(t)cos(2pfct)
• x(t) = Ac [1 + m(t)]cos (2pfct)
• x(t) = Accos(2pfmt)cos(2pfct) + Acsin(2pfmt)sin(2pfct)

Correct Answer:

Explanation:

(C) is without over modulation.