Work done by X in 4 days = | ❨ | 1 | x 4 | ❩ | = | 1 | . |
20 | 5 |
Remaining work = | ❨ | 1 - | 1 | ❩ | = | 4 | . |
5 | 5 |
(X + Y)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 8 | = | 2 | . |
20 | 12 | 60 | 15 |
Now, | 2 | work is done by X and Y in 1 day. |
15 |
So, | 4 | work will be done by X and Y in | ❨ | 15 | x | 4 | ❩ | = 6 days. |
5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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