L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
∴ Required number (9999 - 399) = 9600.
∴ H.C.F. of given numbers = 0.18.
= H.C.F. of 48, 92 and 140 = 4.
Required H.C.F. = | H.C.F. of 9, 12, 18, 21 | = | 3 |
L.C.M. of 10, 25, 35, 40 | 1400 |
By hit and trial, we find that 114345 is divisibleby 11 as well as 9. So, it is divisible by 99.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
∴ The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
84 = 22 x 3 x 7
∴ H.C.F. = 22 x 3 = 12.
On dividing 2497 by 60, the remainder is 37.
∴ Number to be added = (60 - 37) = 23.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
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