The correct pattern is *1+1, *2+2, *3+3, *4+4, . . . . .
So,32 is wrong term and must be replaced by (10 * 3 + 3) = 33
Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get
15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452
Therefore, the missing number is 6630.
The given series follows,
2
2 x 2 = 4
4 x 3 = 12
12 x 4 = 48
48 x 5 = 240.
one of the letter from beginning and one of the letter from the end of a term are removed, one by one, alternate steps
3
3 x 1.5 + 1.5 = 6
6 x 2.5 + 2.5 = 17.5
17.5 x 3.5 + 3.5 = 64.75
64.75 x 4.5 + 4.5 = 295.875
The given number series is 18, 90, 450, 2250, ?
18
18 x 5 = 90
90 x 5 = 450
450 x 5 = 2250
2250 x 5 = 11250
Hence, the next number in the given series is 11250.
Similarly ,
In the given series,
2nd term =
3rd term =
and so on...
Here 6th term =
Therefore, 22 is wrong.
In the given series,
2nd term = 1st term + = 4 +1 = 5
3rd term = 2nd term + =5+4= 9
4th term = 3rd term + =9+9=18
5th term = 4th term + = 18+16=34
Therefore, odd term is 32
The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
It follows the rule that
1
2x2
3x3x3
4x4x4x4
5x5x5x5x5
So the missing number is 4x4x4x4 = 256.
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