Let the rate be R% p.a.
Then,
Rate = 10%
From the given data,
3500x7xt/100 = 500
=> t = 100/49 years
Now, in the second case
The interest per year = 49/100 x 800 = 392
=> 4900 x 1 x r/100 = 392
=> r = 8%
From the information provided we know that,
Principal + 8% p.a. interest on principal for n years = 180 ??.. (1)
Principal + 4% p.a. interest on principal for n years = 120 ??? (2)
Subtracting equation (2) from equation (1), we get
4% p.a. interest on principal for n years = Rs.60.
Now, we can substitute this value in equation (2),
i.e Principal + 60 = 120
= Principal = Rs.60.
We know that SI = , where p is the principal, n the number of years and r the rate percent of interest.
In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.
Therefore, 60 =(60*n*4)/100
=> n = 100/4 = 25 years.
We know that,
I = PTR/100
ATQ,
15800 = 14800 x T x 6/100
T = 15800/148x7
T = 15800/1036
T = 15.25 yrs.
Let sum = S. Then, amount = 7S/6
S.I. = 7S/6 - S = S/6; Time = 3 years.
Rate = (100 x S) / (S x 6 x 3) = 5 5/9 = 50/9 %.
(kx5x1)/100 + [(1500 - k)x6x1]/100 = 85
5k/100 + 90 ? 6k/100 = 85
k/100 = 5
=> k = 500
Clearly, any of the three will give us the answer
Time = (100 x 81)/(450 x 4.5) years
= 4 years.
Let the sum be Rs. p, rate be R% p.a. and time be T years.
Then,
And,
Clearly, from (1) and (2), we cannot find the value of p
So, the data is not sufficient.
Let the Time be 'N' and Rate be 'R'
J = (K x NR)/100 K = (L x NR)/100
J/K = NR/100 K/L = NR/100
J/K = K/L
K x K = JL
Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50
Amount =Rs [ x + (27x/50)] = Rs.77x/50
=> 77X/50 = 2502.50
=>X= (2502.50 * 50)/77 = 1625
Hence Sum = Rs.1625
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