Difficulty: Medium
Correct Answer: 6.3 years
Explanation:
Introduction:
This question tests equating two simple interest amounts from different principals, rates, and times. The core idea is that simple interest is SI = (P * r * t)/100. If two investments produce the same simple interest, we can set their SI expressions equal and solve for the unknown time. Because it involves setting up an equation and solving for time, it is medium difficulty.
Given Data / Assumptions:
Concept / Approach:
Compute SI from case 2 first since all values are known. Then set SI(case 1) equal to that value and solve for t. Keep percentages consistent and remember to divide by 100 only once in each SI formula.
Step-by-Step Solution:
SI2 = (900 * 3.5 * 2) / 100
SI2 = (900 * 7) / 100 = 6300 / 100 = 63
Now set SI1 = SI2:
(200 * 5 * t) / 100 = 63
(1000 * t) / 100 = 63
10t = 63
t = 63 / 10 = 6.3
Verification / Alternative check:
At 5% on ₹200, yearly interest is ₹10. To reach ₹63, time must be 63/10 = 6.3 years, confirming the equation result.
Why Other Options Are Wrong:
5.2 years gives only ₹52 interest. 7 years gives ₹70 interest. 7.9 years gives ₹79 interest. 4.5 years gives ₹45 interest. Only 6.3 years yields ₹63.
Common Pitfalls:
Using 3.5% as 35%, forgetting to multiply by 2 years in case 2, or mixing up principal amounts between the two cases.
Final Answer:
It will take 6.3 years.
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