l1 = 20 cm, A1 = 200 sq cm
? b1 = 200/20 = 10 cm
Now, A2 = 200 x 6/5 = 240 sq cm
b2 = 10 cm
? l2 = 240/10 = 24 cm
? Perimeter of new rectangle = 2(l2 + b2)
= 2(24 + 10) = 2 x 34 = 68 cm
Area of the carpet = Area of the room
= 8 x 6 = 48 sq m
Width of the carpet = 75/100 = 3/4 m
Length of the carpet = 48 x (4/3)
= 16 x 4 = 64 m
? Cost of carpeting = 64 x 20 = ? 1280
According to the question,
l/[2(l + b)] = 5/18
? 10l + 10b = 18l = 10b
? l/b = 10/8 = 5/4
? l : b = 5 : 4
Hence, ratio of length and breadth of a rectangle is 5 : 4
Let length of the rectangular field = 7k m
and breadth of the rectangular field = 2k m
According to the question,
Area of a rectangular field = Length x Breadth
? 3584 = 7k x 2k
? 14 x k2 = 3584
? k2 = 3584/14 = 256
? k2 = 256 = 16 m
? Length of rectangular field = 7k = 7 x 16 = 112 m
And breadth of rectangular field = 2 x 16 = 32 m
? Perimeter of rectangle = 2(Length x Breadth)
= 2(112 + 32)
= 2 x 144
= 288 m
Let l = 4k and b = 9k
Area of rectangle = l x b
144 = 4k x 9k
? k2 = 144/36
? k2 = 4
? k = 2
? l = 8 cm and b = 18 cm
Perimeter of rectangle = 2(l + b)
= 2(8 + 18)
= 2 x 26
= 52 cm
Let length = 2x and breadth = x
According to the question,
2x - x = 5
? x = 5
? Required perimeter = 2(2x + x)
= 6x
= 30 cm
Area to the rectangular field = 12375/15 = 825 sq m
According to the question,
(L x B) = 825 [L = length and B = breadth]
? L x 25 = 825
? L = 825/25 = 33 m
According to the question,
4a = 68 [ where a = side]
?a = 68/4 = 17 cm
? Required area = a2
= (17)2 = 289 sq cm
a1 = 68/4 = 17 cm
and a2 = 60/4 = 15 cm
[ where a1 and a2 are sides]
According to the question,
Area of the third square = [(17)2 - (15)2 ]
= (17 + 15) (17 - 15)
= 32 x 2
= 64 sq cm
Let a3 = Side of the third square.
According to the question, (a3)2 = 64 sq cm
? a3 = ?64 = 8 cm
? Perimeter of the third square = 4 x a3 = 4 x 8 = 32 cm.
Distance covered in 1 revolution
= (44 x 1000) / 4000
= 11 m
According to the question,
2?r = 11
? (44/7) x r = 11
? r = (11 x 7) / 44 = 1.75 m
According to the question,
Area of semi- circle = 77 m
(1/2) x ? x r2 = 77
? r2 = (77 x 2 x 7)/22
? r = 7m
?Circumference of semi- circle =?r + 2r
= ( ? + 2)r
= [(22/7) + 2] x 7
= 36 m
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