Let length = a metres and breadth = b metres
Then, 2(a+b)= 46
? (a+b) =23 and ab =120
? Diagonal = ?a2 + b2
?(23)2-2 x 120
?289 = 17 m
Area of sector = ( arc length x radius ) / 2 cm2
= (3.5 x 5 ) / 2
= 8.75 cm2
Arc length = 2?r (?° / 360°)
= 2 x (22/7) x 21 x (72° / 360°) cm
= 26.4 cm
Area of the sector = [(22/7) x 12 x 12] x [42°/360°] m2
= 52.8 m2
? ?d-d = 105 cm
? (? -1 ) d = 105 cm
? [(22/7)-1] x d = 105 cm
? d = (7/15) x 105 cm = 49 cm
? 2?R - 2?r = (176-132)
? 2?(R-r) = 44
? R-r = ( 44 x 7 )/ (2 x 22)
= 7 m
Speed = 12 x (5/18) m/sec
=10/3 m/sec
there4; perimeter = (10/3) x 15 x 60 m=3000 m
? 2( a + 4a) = 3000 m
? a = 300 m
So, length = 1200 m and breadth = 300 m
? Area = (1200 x 300 ) m2 = 360000m2
Area of a triangle formed by joining the mid point of the sides of the triangle is 1/4th of area of the original triangle .
So area of ? DEF = 36/ 4 = 9 m2
Let the longer side = l, shorter side = b and diagonal = d
Then, area of rectangular carpet = l x b = 60 ....(1)
And from question d + l = 5b
? d = 5b - l ...(2)
? d2 = 25b2 + l2 - 10 x lb
? l2+ b2 = 25b2 + l2 - 10 x lb
? l2+b2 = 25b2 + l2 - 10 x 60
? 24b2 = 600
? b = ?25 = 5 m
? l = 60 / b = 60 / 5 = 12 m
We know that area of triangle = ( base x height ) / 2
So area of triangle = (BC x AD) / 2 = (AC x BE) / 2
? (10 x 4.4) / 2 = (11 x h) / 2
? h= (10 x 4.4)/11 = 4 cm
Cross section area = 1/2 x ( a + b ) x d
where a and b are the parallel sides, d is the perpendicular distance between them.
? 1/2 x ( a + b ) x d = 640
? d = (640 x 2) / 16 = 80m
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