4-bit counter capacity — maximum modulus A binary counter built from 4 flip-flops has what maximum modulus (number of unique states before repeating)?
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A3
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B6
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C8
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D16
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E32
Answer
Correct Answer: 16
Explanation
Introduction / Context:The number of flip-flops determines the maximum count range of a binary counter. Each flip-flop adds one binary digit, doubling the number of available states and thereby increasing the modulus by a factor of two. This is a fundamental design relationship in digital electronics.
Given Data / Assumptions:
- Counter uses 4 flip-flops.
- Binary counting (no skipped states), starting from 0000.
Concept / Approach:An n-bit binary counter can represent 2^n distinct states. For n = 4, the number of states is 2^4 = 16, typically ranging from 0 to 15 in unsigned representation. Unless additional logic truncates the sequence, the natural modulus equals 16.
Step-by-Step Solution:
n = 4 flip-flops ⇒ states = 2^4.Compute 2^4 = 16.Therefore, maximum modulus = 16.Verification / Alternative check:Enumerate outputs from 0000 to 1111. Counting the number of unique 4-bit patterns yields 16, after which the counter repeats at 0000.
Why Other Options Are Wrong:
- 3, 6, 8: correspond to other moduli (e.g., MOD-8 uses 3 flip-flops).
- 32: requires 5 flip-flops (2^5).
Common Pitfalls:
- Confusing modulus with maximum count value; modulus is the number of states (0–15 inclusive gives 16 states).
Final Answer:16