Digital clock timing: required division of the basic frequency In a standard digital clock application, to generate the “tick” that advances the seconds counter, the basic frequency must be divided down to what rate?

Difficulty: Easy

Correct Answer: 1 Hz.

Explanation:


Introduction / Context:
Whether your time base is the mains frequency (50/60 Hz) or a crystal oscillator (for example, 32.768 kHz), a digital clock requires a precise 1 Hz pulse to advance the seconds counter once per second.



Given Data / Assumptions:

  • Seconds increment once each second.
  • Higher-frequency references must be divided (prescaled).
  • Stable division ensures accurate timekeeping.


Concept / Approach:
Use a frequency divider so that the output is 1 tick per second. For a 60 Hz input, divide by 60; for 32.768 kHz, divide by 32,768. The exact divider topology may use cascaded binary or BCD counters in HDL.



Step-by-Step Solution:

Identify the reference frequency.Compute division factor to reach 1 Hz.Implement counters in HDL to realize the division.Feed the 1 Hz output to the seconds counter.


Verification / Alternative check:
Simulate and measure output period; confirm 1 second between rising edges.



Why Other Options Are Wrong:

  • 60 Hz/100 Hz/1000 Hz correspond to upstream references or debounce rates, not the seconds tick.


Common Pitfalls:
Neglecting oscillator tolerance and temperature; consider calibration if needed.



Final Answer:
1 Hz.

More Questions from Digital System Projects Using HDL

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion