Difficulty: Easy
Correct Answer: Incorrect
Explanation:
Introduction / Context:Cutting speed in drilling refers to the surface speed at the cutting edge. Because a drill rotates, the local linear speed depends on radius. Understanding this variation explains chip formation and wear patterns (e.g., higher wear at the outer corners).
Given Data / Assumptions:
Concept / Approach:Linear speed V at a point equals ω * r. At the centre (r = 0), V = 0, so material removal at the chisel edge involves extrusion rather than true cutting. At the periphery (r = D/2), V is maximum. Therefore, cutting speed does not remain the same along the lip.
Step-by-Step Solution:
Angular speed ω = 2πN/60.Local speed V(r) = ω * r → increases with radius.At r = 0 (chisel), V = 0; at r = D/2, V = maximum.Thus, the statement “cutting speed is the same” is incorrect.Verification / Alternative check:Examine chips: little true cutting at the centre, thicker chips near the corners; wear is heavier at outer edges where speed is highest.
Why Other Options Are Wrong:“Correct” would imply uniform linear speed, which contradicts rotational kinematics.
Common Pitfalls:Setting speed based only on material without considering diameter; larger drills require lower rpm to keep peripheral speed within limits.
Final Answer:Incorrect
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