Permutations of BANANA: How many distinct permutations of the letters in BANANA are possible?

Introduction / Context:
BANANA contains repeated letters, so we count distinct permutations by dividing total factorial by repeated-letter factorials.

Given Data / Assumptions:
Letters: A×3, N×2, B×1; total letters = 6.

Concept / Approach:
Distinct permutations = 6! / (3! * 2!).

Step-by-Step Solution:

Verification / Alternative check:
Sanity check with smaller multisets (e.g., AAB) supports the approach.

Why Other Options Are Wrong:
270, 120, 360 are not equal to 6!/(3!*2!).

Common Pitfalls:
Missing one of the repeated-letter divisors.

Final Answer:
60