Arrangements of RECOVER: How many distinct permutations of the letters in RECOVER are possible?

Introduction / Context:RECOVER has repeated letters (R and E). We count distinct permutations by dividing 7! by the factorials of the repeated counts.

Given Data / Assumptions:Total letters = 7; R occurs 2 times; E occurs 2 times; others are distinct.

Concept / Approach:Distinct permutations = 7! / (2! * 2!).

Step-by-Step Solution:

Verification / Alternative check:Check letter counts directly: indeed two Rs and two Es.

Why Other Options Are Wrong:5040 ignores repetition; 1210, 1200 are not equal to 5040/4.

Common Pitfalls:Omitting one of the repeated-letter divisors.

Final Answer:1260