Difficulty: Easy
Correct Answer: 1, 2, 4, 3
Explanation:
Introduction / Context:
Concrete exhibits different strengths depending on the test method and stress state. Understanding the typical hierarchy of strengths helps engineers interpret specifications and convert between test results when necessary.
Given Data / Assumptions:
Concept / Approach:
Typical relationships for normal-strength concrete are: f_c,cube ≈ 1.25 * f_c,cyl (approximate), modulus of rupture f_r ≈ 0.7 * √f_ck (MPa), and split-tensile strength f_t ≈ 0.56 * √f_ck. Thus, compressive strengths are much higher than tensile strengths, and among tensile measures, flexural (modulus of rupture) exceeds split-tension.
Step-by-Step Solution:
Order compressive strengths: cube (1) > cylinder (2).Compare tensile measures: modulus of rupture (4) > split tensile (3).Combine: 1 > 2 > 4 > 3.
Verification / Alternative check:
Code guidance and empirical correlations (e.g., IS/ACI) consistently show cylinder strength lower than cube, and flexural strength higher than split-tensile for the same concrete.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming cube and cylinder strengths are equal; confusing direct tensile with flexural tensile capacity.
Final Answer:
1, 2, 4, 3
Discussion & Comments