Difficulty: Easy
Correct Answer: e n_i (μ_p + μ_n)
Explanation:
Introduction / Context:Intrinsic semiconductors conduct electricity via thermally generated electrons and holes present in equal numbers. Their macroscopic conductivity depends on how many charge carriers exist per unit volume and how easily each carrier drifts under an applied electric field, captured by mobility parameters. This question tests the fundamental expression for conductivity in a pure (undoped) semiconductor.
Given Data / Assumptions:
Concept / Approach:In semiconductors, the drift current density is J = e (n μ_n + p μ_p) E, where E is the electric field. Conductivity σ is defined by J = σ E. For intrinsic material, substitute n = p = n_i to obtain σ = e n_i (μ_n + μ_p).
Step-by-Step Solution:
Start with J = e (n μ_n + p μ_p) E.Use intrinsic condition: n = p = n_i.Then J = e n_i (μ_n + μ_p) E.Hence σ = J / E = e n_i (μ_n + μ_p).Verification / Alternative check:
Dimensional check: e (C) * n_i (m^-3) * μ (m^2/V·s) gives C·m^-1·V^-1·s^-1 = S/m, which is correct for conductivity.Why Other Options Are Wrong:
e n_i (μ_p − μ_n): subtraction is incorrect; both carriers add to conductivity.n_i (μ_p + μ_n): missing the factor e.n_i (μ_p μ_n): wrong functional form; mobilities do not multiply.e (μ_p + μ_n)^2 / n_i: nonphysical dependence on 1/n_i.Common Pitfalls:
Confusing intrinsic with doped material (where n ≠ p) or forgetting the sign of charge (magnitudes are used in σ).Final Answer:
e n_i (μ_p + μ_n)
Discussion & Comments